package geometry; public class Hypotenuse { public InnerTriangle it = new InnerTriangle(); class InnerTriangle { public int base; public int height; } } Which is true about the class of an object that can reference the variable base? ()
第1题:
下面程序的运行结果是
#include<iostream.h>
class base{
protected:
int a;
public:
base( ) {cout < < "0";}
};
class base l: virtual base{
public:
base l ( ) {cout < <"1";}
};
class base 2: virtual base{
public:
base2 ( ) {cout < <"2";}
};
class derived: public base 1, public base2{
public:
derived( ) {cout < < "3";}
};
void main( )
{
derive obj;
cout < < endl;
}
A.0123
B.3120
C.0312
D.3012
第2题:
A.private void fun( int n ){ //...}
B.void fun ( int n ){ //... }
C.protected void fun ( int n ) { //... }
D.public void fun ( int n ) { //... }
第3题:
有以下程序:
included<iostream>
using namespace std;
class Base
{
public:
Base( )
{
x=0;
}
int x;
};
class Derived1:virtual public Base
{
public:
Derived1( )
{
x=10;
}
};
class Derived2:virtual public Base
{
public:
Derived2( )
{
x=20;
}
};
class Derived: public Derived1,protected Derived2
{ };
int main( )
{
Derived obj;
cout<<obj. x<<endl;
return 0;
}
该程序运行后的输出结果是______。
第4题:
有以下程序:
include<iostream>
using namespace std;
class Base
{
public:
Base()
{
K=0;
}
int x;
};
class Derivedl:virtual public Base
{
public:
Derivedl()
{
x=10;
}
};
class Derived2:virtua1 public Base
第5题:
下面程序的运行结果是( )。 #include<iostream.h> class base{ protected: int a; public: base(){cout<<“0”;} }; Class basel:Virtual base{ public: basel(){cout<<“1”;} }; Class base2:virtual base{ public: base2(){cout<<“2”;)
A.0123
B.3120
C.0312
D.3012
第6题:
有如下程序: #include <iostream> using namespace std; class Base { public: Base(int x=0) { cout<<x; } } class Derived: public Base{ public: Derived(int x=0) { cout<<x; } private: Base val; }; int main() { Derived d(1); return 0; }程序的输出结果是
A.0
B.1
C.1
D.1
第7题:
A.It can be any class.
B.No class has access to base.
C.The class must belong to the geometry package.
D.The class must be a subclass of the class Hypotenuse.
第8题:
下面程序的运行结果是
#include
class base
{
protected:
int a;
public:
base(){ cout <<”0”;}
class basel:virtual base
}
public:
base 1(){cout <<”1”;}
};
class base2:virtual base
{
public:
base2(){cout <<”2”;(
};
class derived:public base1,public base2
{
public:
derived(){cout <<”3”;}
};
void main()
{
derived obj;
cout <
}
A.0123
B.3120
C.0312
D.3012
第9题:
有如下程序: #include<iostream> using namespace std; class Base{ public: Base(int x=0){cout<<x;} }; class Derived:public Base{ public: Derived(int x=0){cout<<x;} private: Base val; }; int main( ){ Derived d(1); return 0; } 程序的输出结果是
A.0
B.1
C.01
D.001
第10题:
下列程序的运行结果是______。
include<iostream.h>
class Base
{
public:
void f(int x){cout<<“Base:”<<x<<endl;}
);
class Derived:public Base
{
public:
void f(char*str){cout<<“Derived:”<<str<<endl;}
};
void main(void)
{
Base*pd=ne