Examine the description of the CUSTOMERS table: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50

题目

Examine the description of the CUSTOMERS table: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which statement returns the city address and the number of customers in the cities Los Angeles or San Francisco?()

  • A、SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco');
  • B、SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address;
  • C、SELECT city_address, COUNT(customer_id) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address, customer_id;
  • D、SELECT city_address, COUNT(customer_id) FROM customers GROUP BY city_address IN ('Los Angeles', 'San Francisco');
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相似问题和答案

第1题:

The CUSTOMERS table has these columns:CUSTOMER_ID NUMBER(4) NOT NULLCUSTOMER_NAME VARCHAR2(100) NOT NULLSTREET_ADDRESS VARCHAR2(150)CITY_ADDRESS VARCHAR2(50)STATE_ADDRESS VARCHAR2(50)PROVINCE_ADDRESS VARCHAR2(50)COUNTRY_ADDRESS VARCHAR2(50)POSTAL_CODE VARCHAR2(12)CUSTOMER_PHONE VARCHAR2(20)The CUSTOMER_ID column is the primary key for the table.You need to determine how dispersed your customer base is. Which expression finds the number of different countries represented in the CUSTOMERS table?()

A.COUNT(UPPER(country_address))

B.COUNT(DIFF(UPPER(country_address)))

C.COUNT(UNIQUE(UPPER(country_address)))

D.COUNT DISTINCT UPPER(country_address)

E.COUNT(DISTINCT (UPPER(country_address)))


参考答案:E

第2题:

“雇员”表包含以下列:姓氏VARCHAR2(25) 名字VARCHAR2(25) 电子邮件VARCHAR2(50)如果要编写以下SELECT语句来检索具有电子邮件地址的雇员的姓名。SELECT姓氏||’,’||名字"雇员姓名"FROM雇员;则应使用哪条WHERE子句来完成此条语句?()

  • A、WHERE电子邮件=NULL;
  • B、WHERE电子邮件!=NULL;
  • C、WHERE电子邮件ISNULL;
  • D、WHERE电子邮件ISNOTNULL;

正确答案:D

第3题:

The CUSTOMERS table has these columns:CUSTOMER_ID NUMBER (4) NOT NULLCUSTOMER_NAME VARCHAR2 (100) NOT NULLSTREET_ADDRESS VARCHAR2 (150)CITY_ADDRESS VARHCAR2 (50)STATE_ADDRESS VARCHAR2 (50)PROVINCE_ADDRESS VARCHAR2 (50)COUNTRY_ADDRESS VARCHAR2 (50)POSTAL_CODE VARCHAR2 (12)CUSTOMER_PHONE VARCHAR2 (20)The CUSTOMER_ID column is the primary key for the table.You need to determine how dispersed your customer base is.Which expression finds the number of different countries represented in the CUSTOMERS table?()

A. COUNT(UPPER(country_address))

B. COUNT(DIFF(UPPER(country_address)))

C. COUNT(UNIQUE(UPPER(country_address)))

D. COUNT DISTINTC UPPER(country_address)

E. COUNT(DISTINTC (UPPER(country_address)))


参考答案:E

第4题:

Examine the structure of the EMPLOYEES table: EMPLOYEE_ID NUMBER Primary Key FIRST_NAME VARCHAR2(25) LAST_NAME VARCHAR2(25) Which three statements inserts a row into the table? ()

  • A、INSERT INTO employees VALUES (NULL, 'JOHN','Smith');
  • B、INSERT INTO employees( first_name, last_name) VALUES ('JOHN','Smith');
  • C、INSERT INTO employees VALUES ('1000','JOHN','NULL');
  • D、INSERT INTO employees(first_name,last_name, employee_id) VALUES ('1000, 'john','Smith');
  • E、INSERT INTO employees (employee_id) VALUES (1000);
  • F、INSERT INTO employees (employee_id, first_name, last_name) VALUES ( 1000, 'john',");

正确答案:C,E,F

第5题:

修改表Department添加列Leader数据类型varchar2(10)的语句是:Alter table Department add Leader varchar2(10);


正确答案:错误

第6题:

“雇员”表包含以下列:姓氏VARCHAR2(25) 名字VARCHAR2(25) 电子邮件VARCHAR2(50)如果要编写以下SELECT语句来检索具有电子邮件地址的雇员的姓名。SELECT姓氏||’,’||名字"雇员姓名"FROM雇员;则应使用哪条WHERE子句来完成此条语句?()

  • A、WHERE电子邮件=NULL;
  • B、WHERE电子邮件!=NULL;
  • C、WHERE电子邮件IS NULL;
  • D、WHERE电子邮件IS NOT NULL;

正确答案:D

第7题:

请观察PRODUCT表和SUPPLIER表的结构: PRODUCT PRODUCT_ID NUMBER NOT NULL, Primary Key PRODUCT_NAME VARCHAR2 (25) SUPPLIER_ID NUMBER ( SUPPLIER表的SUPPLIER_ID的外键) LIST_PRICE NUMBER (7,2) COST NUMBER (7,2) QTY_IN_STOCK NUMBER QTY_ON_ORDER NUMBER REORDER_LEVEL NUMBER REORDER_QTY NUMBER SUPPLIER SUPPLIER_ID NUMBER NOT NULL, Primary Key SUPPLIER_NAME VARCHAR2 (25) ADDRESS VARCHAR2 (30) CITY VARCHAR2 (25) REGION VARCHAR2 (10) POSTAL_CODE VARCHAR2 (11) 请评估以下语句: ALTER TABLE suppliers DISABLE CONSTRAINT supplier_id_pk CASCADE; 该语句用于执行什么任务()

  • A、删除引用SUPPLIERS表的所有约束条件
  • B、删除对FOREIGNKEY表的FOREIGNKEY约束条件
  • C、删除引用PRODUCTS表的所有约束条件
  • D、禁用所有依赖于PRODUCTS表的SUPPLIER_ID列的完整性约束条件
  • E、禁用所有依赖于SUPPLIERS表的SUPPLIER_ID列的完整性约束条件

正确答案:E

第8题:

You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns:CUST_ID NUMBER(4) NOT NULLCUST_NAME VARCHAR2(100) NOT NULLCUST_ADDRESS VARCHAR2(150)CUST_PHONE VARCHAR2(20)Which SELECT statement accomplishes this task?()

A. SELECT* FROM customers;

B. SELECT name, address FROM customers;

C. SELECT id, name, address, phone FROM customers;

D. SELECT cust_name, cust_address FROM customers;

E. SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;


参考答案:D

第9题:

The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which two statements find the number of customers? ()

  • A、SELECT TOTAL(*) FROM customer;
  • B、SELECT COUNT(*) FROM customer;
  • C、SELECT TOTAL(customer_id) FROM customer;
  • D、SELECT COUNT(customer_id) FROM customer;
  • E、SELECT COUNT(customers) FROM customer;
  • F、SELECT TOTAL(customer_name) FROM customer;

正确答案:B,D

第10题:

Which statement accomplish this? ()

  • A、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);
  • B、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
  • C、CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);
  • D、CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);
  • E、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);
  • F、CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);

正确答案:B

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