单选题The main point of paragraph 4 is _____.A why geriatric physicians are paid less than other physiciansB why doctors show little interest in being geriatric physiciansC what are the major problems with the elderly care industryD what can be done to ensur

题目

单选题

The main point of paragraph 4 is _____.

why geriatric physicians are paid less than other physicians

why doctors show little interest in being geriatric physicians

what are the major problems with the elderly care industry

what can be done to ensure the healthy development of elderly care

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相似问题和答案

第1题：

（ 29 ）有如下程序：

#include

using namespace std;

class point {

public:

static int number;

public:

point （） {number++;

～ point （） {number-;}

};

imt point::number=0;

void main （） {

point*ptr;

printA,B;

{

point*ptr_point=new point{3};

ptr=ptr_point;

}

pointC;

cout<<POINT::NUMBER<<ENDL;

delete[]ptr;

}

运行时输出的结果是

A ） 3

B ） 4

C ） 6

D ） 7

正确答案：C

第2题：

有如下程序:includeusing namespace std;class Point{public: static int number;

有如下程序：#include＜iostream＞using namespace std；class Point{public： static int number；public： Point(){number++；} ～Point(){number--；}}；int Point::number=0；void main(){ Point*ptr； Point A，B； { Point*ptr_point=new Point[3]； ptr=pb_point； } Point C cout＜＜Point::number＜＜endl； delete[]ptr； }运行时输出的结果是

A．3

B．4

C．6

D．7

正确答案：C
解析：本题考查的知识点是：静态成员，对象的构造，对象的生存周期。静态成员的特性是不管这个类创建了多少个对象，它的静态成员都只有一个拷贝(副本)，这个副本被所有属于这个类的对象共享。本题的Point类中就定义了一个静态成员变量　number。其初始值为0，每次构造则自动增1，析构则自动减1，所以number是Point类对象的计数值。在主函数中，第1行定义了1个Point类型指针ptr，这并不会构造　Point类对象，因此number值为0；第2行定义了2个Point对象，所以此时number值为2；第3～6行是一个语句块，其中通过new运算符又定义了1个包含3个Point对象元素的数组，由于是动态创建的，所以其生命周期只能通过delete运算符来结束，否则会一直占据内存直到程序结束，所以现在number的值为5：第7行定义了1个　Point对象C，number的值变为6；第8行输出number的内容，所以最后输出的结果是6。故本题应该选择C。

第3题：

The main idea of paragraph 4 shows us______.

A. some examples of shooting in the US schools.

B. the American's feeling.

C. some famous schools.

D. that some teachers were killed by students.

正确答案：A

43．答案为A 第四段是校园枪击案的实例列举，因此选A。

第4题：

有以下程序： point(char *p){p+=3；} main() {char b[4]={'a','b'，'c','d'，}，*p=b； point(p)；printf("%c\n",*p); } 程序运行后的输出结果是 ______。

A．a

B．b

C．c

D．d

正确答案：A
解析：在C语言中，函数的参数传递方式采用按值传递，因此不能通过调用函数的方式来改变指针本身的值，只能改变指针所指变量的值。

第5题：

有以下程序: include using namespace std; class Point' { public: void SetPoint(

有以下程序： #include ＜iostream＞ using namespace std; class Point' { public: void SetPoint(int x,int y); void Move(int xOff,int yOff); int GetX() { return X; } int GetY() { return Y; } private: int X,Y; }; void Point::SetPoint(int x, int y) { X=x; Y=y; } void Point: :Move(int xOff, int yOff) X+=xOff; Y+=yOff; } int main () { Point p1; p1.SetPoint(1,2); p1.Move (5, 6); cout＜＜"Point1 is ("＜＜p1.GetX()＜＜','＜＜p1.GetY()＜＜")"＜＜end1; return 0; } 执行后的输出结果是( )。

A．Point1 is (6,8)

B．Point1 is (1,2)

C．Point1 is (5,6)

D．Point1 is (4,4)

正确答案：A
解析：本题考核对象的定义与使用。程序中定义了一个类Point，在主函数中定义了一个Point类的对象p1，然后通过对象p1调用其成员函数SetPoint()和Move()实现移位的操作。

第6题：

and discuss the main arguments for and against the use of a liability disclaimer paragraph. (5 marks)

正确答案：
(c) It has become increasingly common for audit firms to include a disclaimer paragraph within the audit report. However, it is
not a requirement of auditing standards and individual audit firms need to assess the advantages and disadvantages of the
use of a disclaimer paragraph.
The wording is used to state the fact that the auditor’s report is intended solely for the use of the company’s members as a
body, and that no responsibility is accepted or assumed to anyone other than the company and the company’s members as
a body.
The main perceived advantage is that the disclaimer should help to reduce the exposure of the audit firm to liability claims
from anyone other than the company or the company’s body of shareholders. The disclaimer makes it clear that the audit
firm reports only to those who appointed the firm, i.e. the members of the company, and this may make it more difficult for
the audit firm to be sued by a third party.
It is also argued that the use of a disclaimer could help to bridge the ‘expectation gap’ by providing a clearer indication of the
responsibility of the auditor.
In this way the audit firm can manage its risk exposure in an increasingly litigious environment. Recent high profile legal cases
against audit firms, such as the Bannerman case in Scotland, illustrate that an audit firm’s duty of care can extend beyond
the company and its shareholders, and that audit firms should consider how to protect themselves against liability claims.
Tutorial note: It is appropriate here to quote recent cases such as the Bannerman case to illustrate the reason why audit
firms face increased potential exposure to claims from third parties. However, knowledge of specific legal cases is not
required to gain full marks for this requirement.
However, it can be argued that a disclaimer does not necessarily work to protect an audit firm. Each legal case has individual
circumstances, and while a disclaimer might protect the audit firm in one situation, equally it may not offer any protection
where the facts of the case are different.
In addition, it is often argued that if an audit firm conducts an audit using full due care and diligence, there is no need for a
disclaimer, as a high quality audit would be very unlikely to lead to any claims against the audit firm. Consequently, it could
be argued that the use of disclaimers as a means to limit liability could permit low quality audits to be performed, the auditors
being confident that legal cases against them are restricted due to the presence of a disclaimer within the audit report.

第7题：

有以下程序: include point ( char * p) {p ＋ = 3; }main( ) char b[4] = {'a','b','c

有以下程序： #include ＜stdio.h＞point ( char * p) { p + = 3; }main( ) char b[4] = {'a','b','c','d'} , *p=b; point(p); printf( "% c \n" , * p);

A．a

B．b

C．c

D．d

正确答案：A
解析：C函数的参数传递方式采用按值传递，不能通过调用函数改变形参指针本身的值，只能改变指针所指变量的值。调用point函数时，将实参指针p的值(b数组的首地址)传给了形参指针P，P+=3运算使形参指针指向字符d，但并不能改变main函数中p的值，所以本题正确答案应该是选项A)。

第8题：

有以下程序：point(char*p) { *p=’d’; }main(){ char b[4]={’a’,’b’,’c’,’d’},*p=b; Point(p); printf("%c\n",*p);}程序运行后的输出结果是（）。A．a B．b C．c D．d

正确答案：D
函数调用和值传递；*p=b,使p指向b的首地址,*p=’d’,重新对p进行赋值，因为传递的是地址值，所以可以改变实参的的值。

第9题：

下面程序的输出结果是()。includeincludeusing namespace std;class point{p

下面程序的输出结果是( )。 #include＜iostream＞ #include＜math.h＞ using namespace std; class point { private: double x; double y; public: point(double a,double b) { x=a; y=b; } friend double distances(point a,point b); }; double distances(point a,point b) { return sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y)); } int main() { point p1(1,2); point p2(5,2); cout＜＜distances(p1,p2)＜＜end1; return 0; }

A．2

B．4

C．8

D．16

正确答案：B
解析：分析题目，此题最终要实现的结果是sqrt((a.x-b.x)*(a.x-b.x)+(a.y-b.y)*(a.y-b.y))，其中的a.x和a.y分别指p1(1，2)中的1和2。这样容易得到结果是(1-5)*(1-5)+(2-2)*(2-2)=16，再开方得到结果为4。

第10题：

下列程序的输出结果是( )。 char*point(char*pt)： main { char b[4]={a，c，s，f)，*pt=b； pt=point(pt)； printf("％c＼n"，*pt)； } point(char*p) { p+=3； return p； }

A.s

B.c

C.f

D.a

正确答案：C
本题考查函数的调用及参数传递，当执行函数point时，刚开始指针P指向“a”，经过+3，指针p指向“f”，所以最后的输出结果是f。

The main point of paragraph 4 is _____.

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