单选题The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POST

题目

单选题

The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) Which statement finds the rows in the CUSTOMERS table that do not have a postal code? （）

SELECT customer_id, customer_name FROM customers WHERE postal_code CONTAINS NULL;

SELECT customer_id, customer_name FROM customers WHER postal_code = ' ___________';

SELECT customer_id, customer_name FROM customers WHERE postal _ code IS NULL;

SELECT customer_id, customer_name FROM customers WHERE postal code IS NVL;

SELECT customer_id, customer_name FROM customers WHERE postal_code = NULL;

参考答案和解析

正确答案： A

解析：暂无解析

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相似问题和答案

第1题：

The ORDERS table has these columns:ORDER_ID NUMBER(4) NOT NULLCUSTOMER_ID NUMBER(12) NOT NULLORDER_TOTAL NUMBER(10,2)The ORDERS table tracks the Order number, the order total, and the customer to whom the Order belongs.Which two statements retrieve orders with an inclusive total that ranges between 100.00 and 2000.00 dollars? （）

A. SELECT customer_id, order_id, order_total FROM orders RANGE ON order _ total (100 AND 2000) INCLUSIVE;

B. SELECT customer_id, order_id, order_total FROM orders HAVING order _ total BETWEEN 100 and 2000;

C. SELECT customer_id, order_id, order_total FROM orders WHERE order _ total BETWEEN 100 and 2000;

D. SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and <= 2000;

E. SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and order_total <= 2000;

参考答案：C, E

第2题：

单选题

You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: CUST_ID NUMBER(4) NOT NULL CUST_NAME VARCHAR2(100) NOT NULL CUST_ADDRESS VARCHAR2(150) CUST_PHONE VARCHAR2(20) Which SELECT statement accomplishes this task?（）

SELECT* FROM customers;

SELECT name, address FROM customers;

SELECT id, name, address, phone FROM customers;

SELECT cust_name, cust_address FROM customers;

SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;

正确答案： C

解析：暂无解析

第3题：

The PRODUCTS table has these columns:PRODUCT_ID NUMBER(4)PRODUCT_NAME VARCHAR2(45)PRICE NUMBER(8,2)Evaluate this SQL statement:SELECT *FROM PRODUCTSORDER BY price, product _ name;What is true about the SQL statement? （）

A. The results are not sorted.

B. The results are sorted numerically.

C. The results are sorted alphabetically.

D. The results are sorted numerically and then alphabetically.

参考答案：D

第4题：

单选题

The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) A promotional sale is being advertised to the customers in France. Which WHERE clause identifies customers that are located in France?（）

WHERE lower(country_address) = france

WHERE lower(country_address) = 'france'

WHERE lower(country_address) IS 'france'

WHERE lower(country_address) = '%france%'

WHERE lower(country_address) LIKE %france%

正确答案： E

解析：暂无解析

第5题：

单选题

Which statement accomplish this?（）

CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE = SYSDATE);

CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);

CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status VARCHAR2 (10), date_ordered DATE DEFAULT SYSDATE);

CREATE OR REPLACE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);

CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE = SYSDATE);

CREATE TABLE orders ( order_id NUMBER (10), customer_id NUMBER (8), order_status NUMBER (10), date_ordered DATE DEFAULT SYSDATE);

正确答案： C

解析：暂无解析

第6题：

You need to replicate a table from a master to a slave. The master and slave copies of the table will have different number of columns. Which two conditions must be true?（）

A、Each extra column in the copy with more columns must not have a default value
B、Columns that are common to both versions of the table must be defined in the same order on the master and the slave
C、The slave database cannot have more columns than the master. Only the master database can have more columns
D、Columns that are common to both versions of the table must come first in the table definition, before any additional columns are additional columns are defined on either server
E、The master database cannot have more columns than the slave. Only the slave deatbase can have more columns

正确答案:B,D

第7题：

多选题

The ORDERS table has these columns: ORDER_ID NUMBER(4) NOT NULL CUSTOMER_ID NUMBER(12) NOT NULL ORDER_TOTAL NUMBER(10,2) The ORDERS table tracks the Order number, the order total, and the customer to whom the Order belongs. Which two statements retrieve orders with an inclusive total that ranges between 100.00 and 2000.00 dollars? （）

SELECT customer_id, order_id, order_total FROM orders RANGE ON order _ total (100 AND 2000) INCLUSIVE;

SELECT customer_id, order_id, order_total FROM orders HAVING order _ total BETWEEN 100 and 2000;

SELECT customer_id, order_id, order_total FROM orders WHERE order _ total BETWEEN 100 and 2000;

SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and <= 2000;

SELECT customer_id, order_id, order_total FROM orders WHERE order_total>= 100 and order_total <= 2000;

正确答案： B,A

解析：暂无解析

第8题：

The CUSTOMERS table has these columns:CUSTOMER_ID NUMBER (4) NOT NULLCUSTOMER_NAME VARCHAR2 (100) NOT NULLSTREET_ADDRESS VARCHAR2 (150)CITY_ADDRESS VARHCAR2 (50)STATE_ADDRESS VARCHAR2 (50)PROVINCE_ADDRESS VARCHAR2 (50)COUNTRY_ADDRESS VARCHAR2 (50)POSTAL_CODE VARCHAR2 (12)CUSTOMER_PHONE VARCHAR2 (20)The CUSTOMER_ID column is the primary key for the table.You need to determine how dispersed your customer base is.Which expression finds the number of different countries represented in the CUSTOMERS table?（）

A. COUNT(UPPER(country_address))

B. COUNT(DIFF(UPPER(country_address)))

C. COUNT(UNIQUE(UPPER(country_address)))

D. COUNT DISTINTC UPPER(country_address)

E. COUNT(DISTINTC (UPPER(country_address)))

参考答案：E

第9题：

单选题

You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns: Which SELECT statement accomplishes this task?（）

SELECT* FROM customers;

SELECT name, address FROM customers;

SELECT id, name, address, phone FROM customers;

SELECT cust_name, cust_address FROM customers;

SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;

正确答案： C

解析：暂无解析

第10题：

单选题

Examine the description of the CUSTOMERS table: CUSTOMER_ID NUMBER(4) NOT NULL CUSTOMER_NAME VARCHAR2(100) NOT NULL STREET_ADDRESS VARCHAR2(150) CITY_ADDRESS VARCHAR2(50) STATE_ADDRESS VARCHAR2(50) PROVINCE_ADDRESS VARCHAR2(50) COUNTRY_ADDRESS VARCHAR2(50) POSTAL_CODE VARCHAR2(12) CUSTOMER_PHONE VARCHAR2(20) The CUSTOMER_ID column is the primary key for the table. Which statement returns the city address and the number of customers in the cities Los Angeles or San Francisco?（）

SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco');

SELECT city_address, COUNT(*) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address;

SELECT city_address, COUNT(customer_id) FROM customers WHERE city_address IN ('Los Angeles', 'San Francisco') GROUP BY city_address, customer_id;

SELECT city_address, COUNT(customer_id) FROM customers GROUP BY city_address IN ('Los Angeles', 'San Francisco');

正确答案： B

解析：暂无解析

The CUSTOMERS table has these columns: CUSTOMER_ID NUMBER(4)

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