is paid weekly
is adjusted every quarter
is re-examined from year to year
is fixed for the whole contract period
第1题：
阅读以下说明C++代码，将应填入(n)处的字句写在对应栏内。
[说明]
本程序实现了雇员信息管理功能，其中封装了雇员信息及其设置、修改、删除操作。已知当输入为“Smith 31 2960.0”时，程序的输出是：
姓名：Smith 年龄：31 工资：2960
姓名：Smith 年龄：31 工资：3500
姓名：Mary 年龄：23 工资：2500
[C++程序]
include ＜iostream.h＞
include ＜string.h＞
class employee{
char *name; //雇员姓名
short age; //年龄
float salary;//工资
public:
employee();
void set_name(char *);
void set_age(short a) {age=a;}
void set_salary(float s) {salary=s;}
(1);
~ employee(){delete[] name;}
};
employee::employee() { name="";
age=0;
salary=0.0;
void employee::set_name(char *n)
{ name=new char[strlen(n)+1];
(2) (name,n);
}
void employee::print()
{ cout＜＜"姓名":"＜＜name＜＜" 年龄:"＜＜agc＜＜" 工资:" ＜＜salary＜＜endl;
}
void main()
{ char *na;
short ag=0;
float sa=0;
(3);
na=new char[10];
cin＞＞na＞＞ag＞＞sa;
emp.set_name(na);
emp.set_age(ag);
emp.set_salary(sa);
emp.print();
(4) (3500.0);
emp.print();
(5);
emp.set_name("Mary");
emp.set_age(23);
emp.set_salary(2500.0);
emp.print();
}
第2题：
Examine the data of the EMPLOYEES table.EMPLOYEES (EMPLOYEE_ID is the primary key. MGR_ID is the ID of managers and refers to the EMPLOYEE_ID)Which statement lists the ID, name, and salary of the employee, and the ID and name of the employee‘s manager, for all the employees who have a manager and earn more than 4000?（）
A.
B.
C.
D.
E.
第3题：
The salary as ()the contract will be transferred monthly to the representative’s account.
A、in
B、at
C、on
D、within
第4题：
回收用户U1，U2和U3在关系employee的salary属性上的UPDATE限的语句是
A．REVOKE UPDATE(salary) ON employee(U1，U2，U3)
B．REVOKE UPDATE(salary)ON employee FROM U1，U2，U3
C．REVOKE UPDATE ON employee FROM U1，U2，U3
D．REVOKE UPDATE(salary) FROM U1，U2，U3
第5题：
A. The statement produces an error at line 1.
B. The statement produces an error at line 3.
C. The statement produces an error at line 6.
D. The statement returns the employee name, salary, department ID, and maximum salary earned in the department of the employee for all departments that pay less salary then the maximum salary paid in the company.
E. The statement returns the employee name, salary, department ID, and maximum salary earned in the department of the employee for all employees who earn less than the maximum salary in their department.
第6题：
Examine the data in the EMPLOYEES and EMP_HIST tables:The EMP_HIST table is updated at the end of every year. The employee ID, name, job ID, and salary of each existing employee are modified with the latest data. New employee details are added to the table.Which statement accomplishes this task?（）
A.
B.
C.
D.
第7题：
Examine the data in the EMPLOYEES and EMP_HIST tables:EMPLOYEESNAME DEPT_ID MGR_ID JOB_ID SALARYEMPLOYEE_ID101 Smith 20 120 SA_REP 4000102 Martin 10 105 CLERK 2500103 Chris 20 120 IT_ADMIN 4200104 John 30 108 HR_CLERK 2500105 Diana 30 108 IT_ADMIN 5000106 Smith 40 110 AD_ASST 3000108 Jennifer 30 110 HR_DIR 6500110 Bob 40 EX_DIR 8000120 Ravi 20 110 SA_DIR 6500EMP HISTEMPLOYEE_ID NAME JOB_ID SALARY101 Smith SA_CLERK 2000103 Chris IT_CLERK 2200104 John HR_CLERK 2000106 Smith AD_ASST 3000108 Jennifer HR_MGR 4500The EMP_HIST table is updated at the end of every year. The employee ID, name, job ID, and salary of each existing employee are modified with the latest data. New employee details are added to the table.Which statement accomplishes this task?（）
A. UPDATE emp_hist SET employee_id, name, job_id, salary = (SELECT employee_id, name, job_id, salary FROM employees) WHERE employee_id IN (SELECT employee_id FROM employees);
B. MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT VALUES (e.employee id, e.name, job id, e.salary);
C. MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE emp hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employees_id, e.name, e.job_id, e.salary);
D. MERGE INTO emp_hist eh USING employees e WHEN MATCHED THEN UPDATE emp_hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employees_id, e.name, e.job_id, e.salary);
第8题：
授予用户U1，U2和U3在关系employee的salary属性上的UPDATE权限的语句是【 】UPDATE(salary) ON employee TO U1，U2，U3
第9题：
授予用户U1，U2和U3在关系employee的salary属性上的UPDATE权限的语句是
A．GRANT ON employee TOU1，U2，U3
B．GRANT UPDATE ON employee TO U1，U2，U3
C．GRANT UPDATE(salary) ON employee
D．GRANT UPDATE(salary)ON employee TO U1，U2，U3
第10题：
Click the Exhibit button to examine the data of the EMPLOYEES table. Evaluate this SQL statement:SELECT e.employee_id "Emp_id", e.emp_name "Employee", e.salary, m.employee_id "Mgr_id", m.emp_name "Manager"FROM employees e JOIN employees m ON (e.mgr_id = m.employee_id)AND e.salary > 4000;What is its output?（）
A.A
B.B
C.C
D.D
E.E