Behind him Paul could hear the angry man _____ to break the door open.A:tryingB:to tryC:

题目

Behind him Paul could hear the angry man _____ to break the door open.A:trying

B:to try

C:tried

D:try

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相似问题和答案

第1题:

对下面的代码,哪段描述是错误的?() public class Door{ } public class House{ public House(){ Door door = new Door();}}

A.Door是一个类。

B.House是一个从Door继承的类。

C.House的构造函数中声明了一个名为door的变量。

D.door是一个对象。


B

第2题:

I__________have been there,but I__________not find the time.

A.should;would
B.should;could
C.might;could
D.could;could

答案:B
解析:
考查情态动词的用法。句意为:“我本应该去那里,但我没时间。”should have done表示“过去本应做的事而实际上并没有做”,常含有责备、遗憾的语气。

第3题:

Integration ( ) is the process of verifying that the components of a system work together as described in the program design and system design specifications.

A.trying
B.checking
C.testing
D.coding

答案:C
解析:

第4题:

_________________

A. fail B. try C. wish D. bother


正确答案:A

第5题:

Integration ______ is the process of verifying that the components of a system work together as described in the program design an system design specification.

A.trying

B.checking

C.testing

D.coding


正确答案:C
解析:译文的含义是:集成()是这样的过程,它验证系统各个组成部分是否可以按照程序设计和系统设计规范的描述一起工作。选项A、B、C、D的含义分别是尝试、检查、测试、编码。选项C符合题意,为所选。

第6题:

阅读以下说明和C++代码。

【说明】

传输门是传输系统中的重要装置。传输门具有Open(打开)、Closed(关闭)、Opening (正在打开)、StayOpen(保持打开)和Closing(正在关闭)五种状态。触发传输门状态转换的事件有click、complete和timeout三种。事件与其相应的状态转换如下图所示。

下面的C++代码1与C++代码2分别用两种不同的设计思路对传输门进行状态模拟,请填补代码中的空缺。

【C++代码1】

const int CLOSED=1; const int PENING=2;

const int PEN=3; const int CLOSING=4;

const int STAYOPEN=5; //定义状态变量,用不同整数表示不同状态

class Door {

Private:

int state; //传输门当前状态

void setState(int state){ this->state=state;} //设置当前状态

public:

Door():state(CLOSED){};

void getState(){ //根据当前状态输出相应的字符串

switch(state){

case OPENING: cout<<"OPENING"<<endl; break;

case CLOSED: cout<<"CLOSED"<<endl; break;

case OPEN: cout<<"OPEN"<<endl; break;

case CLOSING: cout<<"CLOSING"<<endl; break;

case STAYOPEN:cout<<"STAYOPEN"<<endl; break;

}

};

void click() { //发生click事件时进行状态转换

if ((1)) setState(OPENING);

else if ((2)) setState(CLOSING);

else if ((3)) setState(STAYOPEN);

}

void timeout(){ //发生timeout事件时进行状态转换

if (state == OPEN) setState(CLOSING);

}

void complete(){ //发生complete事件时进行状态转换

if (state == OPENING) setState(OPEN);

else if (state == CLOSING) setState(CLOSED);

}

};

int main(){

Door aDoor;

aDoor.getState();aDoor.click(); aDoor.getState();

aDoor.complete();aDoor.getState(); aDoor.click();

aDoor.getState();aDoor.click(); aDoor.getState(); return 0;

}

【C++代码2】

class Door {

public:

DoorState *CLOSED,*OPENING,*OPEN,*CLOSING,*STAYOPEN,*state;

Door();

virtual~Door(){……//释放申请的内存,此处代码省略);

void setState(DoorState *state) { this->state = state;}

void getState(){

//此处代码省略,本方法输出状态字符串,

//例如,当前状态为CLOSED时,输出字符串为“CLOSED”

};

void click();

void timeout();

void complete();

};

Door::Door(){

CLOSED = new DoorClosed(this); OPENING = new DoorOpening(this);

PEN = new DoorOpen(this); CLOSING = new DoorClosing(this);

STAYOPEN = new DoorStayOpen(this);state = CLOSED;

}

void Door :: click() {(4);)

void Door :: timeout() {(5);)

void Door :: complete() {(6);}

class DoorState//定义一个抽象的状态,它是所有状态类的基类

{

protected:Door *door;

public:

DoorState(Door *door) {this->door = door;}

virtual~DoorState(void);

virtual void click() {}

virtual void complete(


正确答案:(1)state == CLOSED || state == CLOSING (2)state == OPENING || state == STAYOPEN (3)state == OPEN (4)state->click() (5)state->timeout() (6)state->complete() (7)door->setState(door->OPENING)
(1)state == CLOSED || state == CLOSING (2)state == OPENING || state == STAYOPEN (3)state == OPEN (4)state->click() (5)state->timeout() (6)state->complete() (7)door->setState(door->OPENING) 解析:本题考查的是状态转换图的程序设计与实现。
空(1)、(2)和(3)需要根据状态转换图来填写,空(1)、(2)和(3)所在的方法为click,表示当发生click事件时应该发生什么状态转换。根据代码可知,发生click事件时,状态分别跳转到OPENING,CLOSING和STAYOPEN,则发生click前的状态由状态转换图可以得到,分别为CLOSED或CLOSING、STAYOPEN或OPENING以及OPEN。
代码2中空(4)、(5)和(6)考查当发生click、timeout以及complete事件的时候,状态应该如何迁移。类Door的state成员变量用于记录类Door所处的状态,而state变量的类型为DoorState *,DoorState中分别具有click、timeout和complete方法用来响应对应的事件,因此,空(4)、(5)和(6)分别为:state->click()、state->timeout()和 state->complete()。
空(7)主要考查门的当前状态为CLOSED时,发生click事件时状态的迁移。根据状态图可知,CLOSED状态的在click事件下将迁移到OPENING,因此,此处应该将传输门状态设置为OPENING,DoorState变量存储了当前其存储的传输门的实例,因此,可直接调用其方法setState来设置状态,由于传输门状态采用类的实例变量表示,所以此处应该填写door->setState(door->OPENING)。
代码1和代码2的区别是:代码2将状态间的转换规则封装到具体的类中,当状态转换图的转换规则发生变化时,只需更改部分对应类中的状态迁移规则,而代码1中的迁移规则散落在程序中,维护起来较为困难。

第7题:

YouareimplementinganASP.NETpagethatincludesthefollowingdrop-downlist.Youneedtodynamicallyaddvaluestotheendofthedrop-downlist.Whatshouldyoudo?()

A.AddthefollowingOnPreRendereventhandlertotheasp:DropDownList

B.AddthefollowingOnPreRendereventhandlertotheasp:DropDownList

C.Addthefollowingeventhandlertothepagecode-behind.

D.Addthefollowingeventhandlertothepagecode-behind.


参考答案:B

第8题:

John: Paul, this is Mr Smith, my landlord.

Paul: I'm pleased to meet you.

Mr Smith: ( ).

A. Good morning, Paul.

B. Very pleased to meet you, too.

C. I'm fine, too.


正确答案:B

第9题:

整箱货的交接方式有()。

A.CY-CY

B.CY-DOOR

C.DOOR-CY

D.DOOR-DOOR


正确答案:ABCD