A、how long you live here
B、how long have you lived here
C、how long you have lived here
D、how long did you live here
第1题:
下列程序执行后的输出结果是
#included<string.h>
main( )
{ char arr[2][4];
strcpy(arr,"you");strepy(arr[1],"me");
arr[0][3]='&';
cout<<arr<<endl;
}
A.you&me
B.you
C.me
D.err
第2题:
A、inform
B、uniform
C、tall
D、tell
第3题:
此题为判断题(对,错)。
第4题:
Me,you是两个初始集合,则下列关于派生集合定义方式正确的是
A.link/me,you/:a;
B.link(me,you):a;
C.link/me you/a;
D.link(me,you)/a;
第5题:
49.—What about some drinks?
—__________.
A. Help, yourself
B. Good idea
C. You're welcome
D. Me,too
第6题:
A、must misunderstand
B、must have misunderstood
C、must be misunderstanding
D、had to misunderstand
第7题:
下列程序执行后的输出结果是______。 main() { char arr[2][4]; atrcpy(arr,"you");strcpy(arr[1],"me"); art[0][3]='&'; printf("%s\n",arr); }
A.you&me
B.you
C.me
D.err
第8题:
Could you ____ me how to ________ this word in English? (
A. tell, speak
B. speak, say
C. tell, say
D. say, speak
第9题:
第10题:
me是一个包含3个成员属性为a的集合,you是一个包含2个成员属性为b的集合,则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是
A.ps(me,you):c;
B.ps(you,me):c;
C.ps(a,b):c;
D.ps(b,a):c;