填空题The members of set O are the integer solutions of the inequality 3x-4 ≤11, and the members of set P are the integer solutions of the inequality-4x+5-7. What is one member of the intersection of O and P ?____

以下用户自定义函数 Function Func(a As Integer，b As Integer)As Integer Static m As Integer．i As Integer m=0：i=2 i=i+m+i m=i+a-i-b Func=m End Function 在窗体上画一个命令按钮，然后编写如下事件过程： Private Sub Command1_Click() Dim k As Integer，m As Integer，p As Integer k=4：m=1 P=Func(k,m) Print P End Sub 程序运行后，单击命令按钮，输出结果为

A．8

B．9

C．10

D．11

A、Managers should order all member work together.

B、Coach set strict rules for all the team members to obey.

C、Team members should be persuaded to cooperate with each other.

D、Team members should learn to show off personal ability.

单击命令按钮时，下列程序的执行结果为

Private Sub Command1_Click（）

Dim a As Integer, b As Integer, c As Integer

a=2: b=3: c=4

Print P2（c, b, A．

End Sub

Private Function P1（x As Integer, y As Integer, z As Integer）

P1=2 * x + y + 3 * z

End Function

Private Function P2（x As Integer, y As Integer, z As Integer）

P2=P1（z, x, y） + x

End Function （ ）。

A．21

B．19

C．17

D．34

有如下程序： Private Sub Command1_Click() Dim k As Integer，m As Integer Dim p As Integer k=4：m=1 p=PC(k，m)：Print p； p=PC(k，m)：Print p End Sub Private Function PC(a As Integer，b As Integer) Static m As Integer，i As Integer m=0：i=2 i=i + m + 1 m=i + a + b PC=m End Function 程序运行后，输出的结果为

A．4 6

B．6 6

C．8 8

D．10 12

A Windows Communication Foundation (WCF) service is generating a separate namespace declaration for each body member of a message contract,even though all body members share the same namespace. You need to simplify the XML representation of your message contract so that the namespace is only declared once. What should you do?（）

A. Declare a wrapper namespace for the message contract by using the WrapperNamespace property of the MessageContract attribute

B. Explicitly set the Namespace property of all the MessageBodyMember attrbutes to the same namespace.

C. Declare all of the body members as properties of a DataContract class and use the class as the only body member of the message contract.

D. Declare all of the body members as properties of a separate MessageContract class and use the class as the only body member of the message contract.

（27）下列函数过程 Function Func（a As Integer,b As Integer）As Integer Static m As Integer,i As Integer M=0 i=2 A=i+m+1 b=i+a+b Func2=m End Function Private Sub Command1_Click() Dim p As Integer,k As Integer,m As Integer k=4 m=1 P=Func2(k,m) Print k;m End Sub程序运行后，单击命令按钮，输出结果是 A.3 6<CR>3 6 B.3 6<CR>3 11C.3 11<CR>3 6 D.3 11<CR>3 11

设程序中有如下数组定义和过程调用语句： Dim a(10)As Integer … Call D(a) 如下过程定义巾，正确的是（ ）。

A.Private Sub p(a As Integer)

B.Private Sub p(a（ ）As Integer)

C.Private Sub p(a(10)As Integer)

D.Private Sub p(a(n)As Integer)

下列程序运行后，单击命令按钮，窗体显示的结果为( )。 Private Function pl(x As Integer,y As Integer,z As Integer) pl=2*x+y+3*z End Function Private Function p2(X As Integer,y As Integer,z As Integer) p2=p1(z,y,x)+x End Function Private Sub Commandl_Click()

A．23

B．19

C．21

D．22

单击命令按钮时，下列程序的执行结果为 Private Sub Command1_Click() Dim a As Integer，b As Integer，c As Integer a=2：b=3：C=4 Print P2(c，b，A)End Sub Private Function P1(x As Integer，y As Integer，z As Integer) P1=2 * X + y + 3 * z End Function Private Function P2(x As Integer，y As Integer，z As Integer) P2=P1(z，x，y) + X End Function

A．21

B．19

C．17

D．34

在窗体上画一个命令按钮，然后编写如下事件过程：Private Sub Command1_Click( ) Dim m As Integer，n As Integer，p As Integer m=3：n=5：p=O Call Y(m，n，p) Print Str(p)End SubSub Y(ByVal i As Integer，ByVal j As Integer，k As Integer) k=i + jEnd Sub程序运行后，如果单击命令按钮，则在窗体上显示的内容是

A．4

B．6

C．8

D．10