I ____ the movie ____ one of the worst I've ever seen.

乳牙萌出的顺序为

A．I→Ⅱ→Ⅳ→Ⅲ→V

B．I→Ⅱ→Ⅲ→]V→V

C．I→Ⅲ→Ⅱ→Ⅳ→V

D．Ⅱ→I→Ⅲ→Ⅳ→V

E．Ⅱ→I→Ⅳ→Ⅲ→V

I've _____ these lines again and again but I still keep forgetting them.

A. gone off

B. gone about

C. gone over

D. gone through

Techniques that can improve communication include:

A establishing a single, one-way communications channel

B avoiding face-to-face communication

C using redundancy (i.e. saying it two different ways) whenever possible

D disregarding the sensitivity of your receiver

E All of the above.

执行下列程序，显示的结果是【 】。

ne="WORK"

two=""

a=LEN(one)

i=a

DO WHILE i＞=l

two=two+SUBSTR(one,i, 1)

i=i-1

ENDDO

?two

（ 10 ）执行下列程序，显示的结果是 【 10 】 。

one= "WORK"

two = ""

a = LEN ( one )

i = a

DO WHILE i>=1

two = two + SUBSTR ( one ,i , 1 ）

i=i - 1

ENDDO

? two

A. what

B. any

C. which

D. that

--I need some thing for cut ting the paper.

--Oh,you wan takn ife?OK,I'llget______foryou.

A.it

B.that

C.this

D.one

B 宽度优先（种子染色法）

5．关键路径

几个定义： 顶点1为源点，n为汇点。

a. 顶点事件最早发生时间Ve[j], Ve [j] = max{ Ve [j] + w[I,j] },其中Ve (1) = 0;

b. 顶点事件最晚发生时间 Vl[j], Vl [j] = min{ Vl[j] – w[I,j] },其中 Vl(n) = Ve(n);

c. 边活动最早开始时间 Ee[I], 若边I由<j,k>表示，则Ee[I] = Ve[j];

d. 边活动最晚开始时间 El[I], 若边I由<j,k>表示，则El[I] = Vl[k] – w[j,k];

若 Ee[j] = El[j] ，则活动j为关键活动，由关键活动组成的路径为关键路径。

求解方法：

a. 从源点起topsort,判断是否有回路并计算Ve;