31 "Hard logic" in the preparation of a network refers to:
A. Discretionay dependencies
B. External depenencies
C. Mandatory dependencies
D. All of the above
E. A abd B only
第1题:
A.<logic:equal>
B.<logic:lessEqual>
C.<logic:lessThan>
D.<logic:notEqual>
第2题:
----Hard-a-port! ----Hard-a-port! __________!
A.Hard-a-port
B.Wheel hard-a-port
C.Wheel on hard-a-port
D.Yes
第3题:
A.std_logic_arith、std_logic_unsigned、std_logic_signed
B.std_logic_arith、std_logic_unsigned、std_logic_1164
C.std_logic_unsigned、std_logic_1164、std_logic_arith
D.std_logic_1164、std_logic_arith、std_logic_unsigned、std_logic_signed
第4题:
7、实验任务2用32*32的RAM实现寄存器堆,选出合适的存储器描述
A.localparam MEMDEPTH=1<<5 logic [31:0] mem [MEMDEPTH-1]
B.localparam MEMDEPTH=32; logic [31:0] mem [0:MEMDEPTH];
C.localparam MEMDEPTH=1<<5 logic [4:0] mem [0:MEMDEPTH]
D.localparam MEMDEPTH=2**5; logic [4:0] mem [0:MEMDEPTH-1];
第5题:
STD_LOGIC_1164程序包的正确声明方法是?
A.USE STD_LOGIC_1164
B.USE IEEE.STD_LOGIC_1164
C.USE IEEE.STD_LOGIC_1164.ALL
D.USE
第6题:
[A] relates [B] refers [C] responds [D] resorts
本题考查动词词义的辨析。空格处填入的动词应与to搭配,并符合文意。由前文的They don’t listen to each other(他们对对方的话充耳不闻)可知,[C]项responds“作答,作出反应,响应”符合文意,如The government responded to pressure and dropped the proposal(政府感受到压力之后撤销了那项提议),原文意为:每个人对对方传达的确切信息都毫无反应。Relate to“和……有关;欣赏,领略”,如I can’t relate to that kind of music(我不能欣赏那种音乐);refer to“提到,指称;参考”,如He often referred to notes while speaking(他演讲时常看讲稿);resort to“常去;求助,诉诸”,如If persuasion won’t work, we may have to resort to force(如果说服工作不见效,我们可能只得诉诸武力)。
第7题:
STD_LOGIC_1164程序包的正确声明方法是()
A.USE STD_LOGIC_1164
B.USE IEEE.STD_LOGIC_1164
C.USE IEEE.STD_LOGIC_1164.ALL
D.USE STD_LOGIC_1164.ALL
第8题:
A.<logic:equal>
B.<logic:present>
C.<logic:notPresent>
D.<logic:notEqual>
第9题:
程序包()重载了可用于INTEGER型及STD_LOGIC和STD_ LOGIC_VECTOR型混合运算的运算符,并定义了一个由STD_LOGIC_VECTOR型到INTEGER型的转换函数。
A.STD_LOGIC_SIGNED
B.STD_LOGIC_ARITH
C.STD_LOGIC_UNSIGNED
D.STD_LOGIC_1164
第10题:
7、实验内容2用32*32的RAM实现寄存器堆,选出合适的存储器描述
A.localparam MEMDEPTH=1<<5 logic [31:0] mem [MEMDEPTH-1]
B.localparam MEMDEPTH=32; logic [31:0] mem [0:MEMDEPTH];
C.localparam MEMDEPTH=1<<5 logic [4:0] mem [0:MEMDEPTH]
D.localparam MEMDEPTH=2**5; logic [4:0] mem [0:MEMDEPTH-1];