To load a base operating system on a machine using NIM, what are the minimum NIM resources that must be defined for the installation to succeed?()
第1题:
下面程序的运行结果是
#include
class base
{
protected:
int a;
public:
base(){ cout <<”0”;}
class basel:virtual base
}
public:
base 1(){cout <<”1”;}
};
class base2:virtual base
{
public:
base2(){cout <<”2”;(
};
class derived:public base1,public base2
{
public:
derived(){cout <<”3”;}
};
void main()
{
derived obj;
cout <
}
A.0123
B.3120
C.0312
D.3012
第2题:
A.100Base-TX
B.10Base-2
C.1000Base-SX
D.1000Base-LX
第3题:
A、Load,Init ,Activate
B、Init ,Load,Activate
C、Load,Activate ,Init
D、Init ,Load,Activate
第4题:
Ethernet 的物理层协议主要有(21)。
A.10BASE-T1000BASE-T FDDI
B.10BASE-T 100BASE-T 1000BASE-T
C.100BASE-T 1000BASE-T FDDI
D.10BASE-T 100BASE-T FDDI
第5题:
B.<load-on-startup>1</load-on-startup>
C.<load-on-startup>-1</load-on-startup>
D.<load-on-startup>true</load-on-startup>
第6题:
下面程序的运行结果是
#include<iostream.h>
class base{
protected:
int a;
public:
base( ) {cout < < "0";}
};
class base l: virtual base{
public:
base l ( ) {cout < <"1";}
};
class base 2: virtual base{
public:
base2 ( ) {cout < <"2";}
};
class derived: public base 1, public base2{
public:
derived( ) {cout < < "3";}
};
void main( )
{
derive obj;
cout < < endl;
}
A.0123
B.3120
C.0312
D.3012
第7题:
A.10BASE.T
B.100BASE.T
C.10BASE.T/100BASE.T
D.10BASE.T/1000BASE.T
第8题:
在FoxPro命令窗口,输入并执行下列命令后,
use base
打开的数据库文件名是( )。
A.base.dbf
B.base.gpr
C.base.mpr
D.base.bak
第9题:
下面程序的运行结果是 #include<iostream.h> class base{ protected: int a; public: base( ){cout<<"0";} }; class basel:virtual base { public: base1( ){cout<<"1";} }; class base2:virtual base{ public:
A.123
B.3120
C.312
D.3012
第10题:
有如下程序:
include<iostream>
using namespace std
class Base{
int b;
public:
Base(int i) {b=i;}
Void disp ( ) {cout<<"Base:b="<<b<<''; }
};
class Base1:virtual public Base{
public:
Base1(int i):Base(i){}
};
class Base2:virtual public Base{
public:
Base2(int i):Base(i){}
};
class Derived:public Basepublic Base1{
int d;
public:
Derived(int i ,int j):Base1(j),Base2(j),【 】
{ d=i; }
void disp() {cout<<"Derived:d="<<d<<' ';}
};
int main()
Derived objD(1,2);objD. disp()
objD. Base::disp();
objD. Base1::disp()
objD. Base2::disp();
return 0;
}
请将程序补充完整,使程序在运行时输出:
Derivd:d=1 Base:b=2 Base:b=2 Base:b=2