A customer is concerned about rising power costs, and the limited space they have left in the computer room. They have been doing some research into virtualization and would like to know if they should pursue this solution.Which of the following architect

题目

A customer is concerned about rising power costs, and the limited space they have left in the computer room. They have been doing some research into virtualization and would like to know if they should pursue this solution.Which of the following architectural features should be discussed with them?（）

A、x3650 M3 servers and racks
B、x3550 M3 servers, VMware and racks
C、BladeCenter, blades and VMware
D、x3620 M3 servers and VMware

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相似问题和答案

第1题：

CRM的最常用的意思是( )。

A.Customer Relationship Management Services

B.Customer Request Management

C.Customer Relationship Manager

D.Co-operation Relationship Management

正确答案：A

第2题：

下面的XML片断中结构完整的是（）。

A、＜customer name=”＜xml＞.con”＞＜address＞123 MainStreet＞＜/address＞＜/customer＞
B、＜customer＞＜name＞Joe’s XML Works＜/name＞＜address＞New York＜/costomer＞
C、＜ customer type=extemal＞＜name＞Partners Unlimited＜/name＞＜/customer＞
D、＜customer name=”John Doe”＞＜address＞123 Main Street＜/address＞＜zip code=”01837”/＞＜/customer＞

正确答案:D

第3题：

The most important customer a technician has is:()

A. the customer standing right in front of them.

B. the customer who owes the company the most money.

C. the customer calling on the phone.

D. the customer they have an appointment with in an hour.

参考答案：A

第4题：

Which VPN router does not contain customer routing knowledge?（）

A、Provider Core (P)
B、Provider Edge (PE)
C、Customer Edge (CE)
D、Customer Boundary (CB)

正确答案:A

第5题：

A customer has ordered a rack， a p650， two p630s， and two p615s. During a conversation on installation planning， the pSeries technical specialist recognizes that the customer expects the rack to arrive as one unit. However， the specialist knows that the p650 will be racked， but the other systems will arrive separately. In fact， the other systems are CSU （Customer Set Up）. Why should the specialist immediately inform the customer that additional racking is the customer’s responsibility？（）

A、Because additional systems would require more power receptacles
B、Because the customer may need to do additional facilities planning
C、Because the customer needs additional funding to cover the services
D、Because postponing the eventual discussion will likely lead to customer dissatisfaction

正确答案:D

第6题：

当需要删除某个序列seq_customer_id,可以使用如下()方式。

A.DROP SEQ_CUSTOMER_ID

B.DELETE SEQUENCE SEQ_CUSTOMER_ID

C.DROP SEQUENCE SEQ_CUSTOMER_ID

D.DELETE SEQ_CUSTOMER_ID

参考答案：C

第7题：

The most important customer a technician has is:（）

A、the customer standing right in front of them.
B、the customer who owes the company the most money.
C、the customer calling on the phone.
D、the customer they have an appointment with in an hour.

正确答案:A

第8题：

阅读以下说明和 Java程序，填补代码中的空缺，将解答填入答题纸的对应栏内。【说明】以下Java代码实现一个简单客户关系管理系统（CRM）中通过工厂（CustomerFactory ）对象来创建客户（Customer）对象的功能。客户分为创建成功的客户（RealCustomer）和空客户（NullCustomer）。空客户对象是当不满足特定条件时创建或获取的对象。类间关系如图 5-1 所示。图5-1 类图

【Java代码】 Abstract class Customer﹛ Protected String name; （ 1 ）boolean isNil(); （ 2 ）String getName(); ﹜ Class RealCustomer （ 3 ）Customer{ Public RealCustomer(String name){ this.name=name; } Public String getName(){ return name ; } Public boolean is Nil() { return false; } ﹜ Class NullCustomer（ 4 ）Customer﹛ Public String getName()﹛ return "Not Available in Customer Database"; ﹜ Public boolean isNil() ﹛ return true; ﹜ ﹜ class Customerfactory { public String[] names = {"Rob"，"Joe"，"Julie"}; public Customer getCustomer(String name) { for (int i = 0; i < names.length;i++) { if (names[i].（ 5 ）)﹛ return new RealCustomer(name); ﹜ ﹜ return （ 6 ）; ﹜ ﹜ Public class CrM﹛ Public viod get Customer()﹛ Customerfactory（ 7 ）; Customer customer1-cf.getCustomer("Rob"); Customer customer2=cf.getCustomer("Bob"); Customer customer3= cf.getCustomer("Julie"); Customer customer4= cf.getCustomer("Laura"); System.out.println("customers”) System.out.println(customer1.getName()); System.out.println(customer2getName()); System.out.println(customer3.getName()); System.out.println(customer4.getName()); ﹜ Public static viod main (String[]arge)﹛ CRM crm =new CRM(); Crm.getCustomer(); ﹜ ﹜ /*程序输出为： Customers rob Not Available in Customer Database Julie Not Available in Customer Database */

正确答案：1）public abstract
2) public abstract
3)extends
4)extends
5)equals(name)
6)new Null Customer()
7) cf=New CustomerFactory();

第9题：

The customer has recently installed a pSeries p5-570 with EMC attached disk storage. After installation， the customer complained that the disk access appeared to be too slow. How should the pSeries technical specialist best assist the customer？（）

A、Recommend the customer call EMC.
B、Recommend the customer call IBM hardware support.
C、Recommend the customer contact SupportLine.
D、Recommend the customer re-creates the volume groups.

正确答案:C

第10题：

（）is software about the relation between the customer and the supplier in marketing.

A、Customer Relationship Management
B、Customer service
C、Sales planning
D、Distribution channel

正确答案:A

A customer is

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